James B. answered 06/25/16
Tutor
5.0
(3,069)
Common Core Mathematics
Let k = # of kilometers driven
COMPANY 1:
fixed fee = $45
km charge = 1.50k ($1.50 for each km driven)
Cost function: f(k) = 1.50k + 45
Determine the distance driven:
Rate • Time = Distance
100 km/hr • 6 hr = 600 km
Plug 600 into the Cost function
f(600) = 1.50(600) + 45
= $945
COMPANY 2:
fixed fee = $40
km charge = 1.65k ($1.65 for each km driven)
Cost function: g(k) = 1.65k + 40
Number of miles driven is 600 km (sane as for company 1)
fixed fee = $40
km charge = 1.65k ($1.65 for each km driven)
Cost function: g(k) = 1.65k + 40
Number of miles driven is 600 km (sane as for company 1)
Plug 600 into the Cost function
g(600) = 1.65(600) + 40
= $1030
clearly, company 1 is the better deal (cheaper cost) ... f(600) < g(600)
The problem asked to use composite functions.
I will use
f(k) = 1.50k + 45 (company 1)
g(k) = 1.65k + 40 (company 2)
(f - g)(k) = f(k) - g(k)
= (1.50k + 45) - (1.65k + 40)
= 1.50k + 45 = 1.65 - 40
= -.15k + 5
(f - g)(600) = -.15(600) + 5 = -85
(g - f)(k) = g(k) - f(k)
= (1.65k + 40) - (1.50k + 45)
= 1.65k + 40 - 1.50k - 45
= .15k - 5
(g - f)(600) = .15(600) - 5
= 85
The difference in cost is $85