Patrick D. answered 03/27/17
Tutor
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Patrick the Math Doctor
There are three unknown quantities, so three equations are needed:
A + B + C = 560
A = 2B --> B = A/2
C = 2A
Substituting the last two equations into the first gives:
A + B + C = 560
A + A/2 + 2A = 560 because B = A/2 per the second equation and C = 2A per the third equation
Multiplying both sides by two to clear the fraction, the equation becomes:
2A + A + 4A = 1120
7A = 1120 <-- after combining like terms
A = 160
B = A/2 = 160/20 = 80
C = 2A = 2*160 = 320
Finally, A + B + C = 160 + 80 +320 = 560