Raymond B. answered 08/01/21
Math, microeconomics or criminal justice
f(x)= x^2 - 9x
f(x+h) = (x+h)^2 - 9(x+h) = x^2 +2xh+h^2 -9x-9h
f(x+h)-f(x) = x^2+2xh+h^2-9x-9h -x^2+9x
the x^2 and x terms cancel leaving
f(x+h)-f(x) = 2xh+h^2 -9h
[f(x+h)-f(x)]/h = 2x+h -9
if you took the limit as h approaches zero then the limit of [f(x+h) -f(x)]/h would approach 2x +0 -9 = 2x-9
which is the derivative of f(x)=x^2-9x or f'(x)=2x-9