Mike R. answered 09/26/16
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Math Teacher, Regents, AP, SAT, ACT
Let's create 3 different equations, one for each person. We will assign the variable "b" for burritos, "m" for milk, and "h" for hashbrowns:
Chery
5b + 3m + 15h = 41
Sam
8b + m + 3h = 37
Karla
3b + 4m + 6h = 26
Solve the system of equations by using the elimination method. I am going to multiply Sam's equation times (-3), so that the variable "m" cancels out when adding Chery's and Sam's equations together [8b + m + 3h = 37 turns into -24b - 3m - 9h = -111].
5b + 3m + 15h = 41
-24b - 3m - 9h = -111
____________________
-19b + 6h = -70
Now, I am going to multiply Sam's equation times (-4), so that the variable "m" cancels out when adding Karla's and Sam's equations together [8b + m + 3h = 37 turns into -32b - 4m - 12h = -148].
3b + 4m + 6h = 26
-32b - 4m - 12h = -148
____________________
-29b - 6h = -122
3b + 4m + 6h = 26
-32b - 4m - 12h = -148
____________________
-29b - 6h = -122
Now we have two equations, each having the two variables "b" and "h". Since one equation has "+6h" and the other has "-6h", if we add these two equations together, the variable "h" will be cancelled altogether.
-19b + 6h = -70
-29b - 6h = -122
_______________
-48b = -192
b = 4
Now that we found that b = 4, we can substitute that value into either of the two equations that have "b" and "h", and then we can solve for "h".
-19b + 6h = -70
-19(4) + 6h = -70
6h = 6
h = 1
Now that we found that b = 4 and h = 1, we can substitute those values into any of the three original equations that have "b" "h" and "m", and then we can solve for "m".
8b + m + 3h = 37
8(4) + m + 3(1) = 37
32 + m + 3 = 37
m + 35 = 37
m = 2
The burritos cost $4, the milk cost $2, and the hash browns cost $1.