help simplify sqrt 9y - 196

Question

would you please help me find where I went wrong on simplifing and solving this problem

  _______

√9y - 196  +  √196 = √49

 

√9y - √196 + √196 = √49

 

    √9y = √49

 

    3y = 7

 

 

I dont think this is the right answer

Answer 1

√(9y-196)+ √196=√49

√(9y-196)+ 14=7

√(9y-196)+14-14=7-14

√(9y-196)=-7

no solution because the square root must be positive or 0

Answer 2

√49 = 7 and √(196) = 14

 

(9y - 196)^(1/2) + (196)^(1/2) = √49 = 7

 

(9y - 196)^(1/2) = 7 - 14

 

L, there is no real value of y for which this is true since we're requiring (9y - 196)^(1/2) to be < 0.

 

 

Answer 3

You can't break √(9y-196) as √9y-√196.

 

I would start with noticing that √196=14 and √49=7

 

Therefore, we have:

 

√(9y-196)+14=7

 

Or √(9y-196)=-7

 

Since square root must give you positive number, this equation does not have any solutions.