
Steve S. answered 01/20/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
Assuming this is what you meant:
√(135b^2c^3d) * √(5b^2d), where * means multiply,
d >= 0 so second radical is not imaginary, and
c >= 0 so first radical is not imaginary;
then the expression can be expanded to:
√(135) * √(b^2) * √(c^2) * √(c) * √(d) * √(5) * √(b^2) * √(d)
√(3*3*3*5) * √(5) * (√(b^2))^2 * c * √(c) * (√(d))^2
√(3*3*3*5*5) * b^2 * c√(c) * d
3*5*√(3) * b^2 * c√(c) * d
15*√(3) * b^2 * c√(c) * d
15 * b^2 * c * d * √(3c)