Write an equation in slope-intercept form for the line that passes through (-5,3) and is perpendicular to the line described by y= 5x.

Hi Haley;

*Write an equation in slope-intercept form for the line that passes through (-5,3) and is perpendicular to the line described by y= 5x.*

The equation is in slope-intercept form...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

y=5x

Slope is 5

y-intercept is zero. However, this will be a non-issue when establishing the perpendicular equation.

In such equation, the slope is -1/5.

y=(-1/5)x+b

Let's apply the point-slope formula...

(y-y

_{1})=m(x-x_{1})y-3=(-1/5)(x--5)

y-3=(-1/5)(x+5)

y-3=(-1/5)x-1

y=(-1/5)x+2