
Arturo O. answered 09/16/16
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1)
The consecutive odd integers are n and n + 2.
n(n + 2) = 143
n2 + 2n - 143 = 0
Note we can factor the quadratic equation above.
(n + 13)(n - 11) = 0
This gives two values of n: n = -13, 11
So there are two pairs of consecutive odd integers that when multiplied give 143:
(i) -13 and -11
(ii) 11 and 13
2)
A = L2
P = 4L
If numerically equal (ignoring units), then
A = P ⇒ L2 = 4L
L = 4
A = L2
P = 4L
If numerically equal (ignoring units), then
A = P ⇒ L2 = 4L
L = 4
3)
s = 220t - 16t2
750 = 220t - 16t2
Divide through by 2 to simplify a little:
375 = 110t - 8t2
8t2 - 110t + 375 = 0
t = [1/(2*8)] {110 ± √[(110)2 - 4(8)(375)]} = (1/16) (110 ± 10) = 6.25 or 7.5 seconds
There are two times:
At t1 = 6.25 s, it reaches 750 ft on the way up, and at t2 = 7.5 seconds, it reaches 750 ft again on the way down.