sam has a total of 58 DVD`s and CD`s.if the number of two more than three times the number of DVD`s how many CD `s are there

Question

i dont under stand about the question i =ts very hard brothr wont help me

 

Answer 1

I believe there is a typo in your question so that makes it a little harder to answer. However, I believe in the second sentence you meant to type "If the number of CD's is two more than three times the number of DVD's", right?

 

First of all you might assign variables to the items you are talking about. You can use C for CD's and D for DVD's, or x for CD's and y for DVD's. The variable that you choose does not matter as long as you are consistent. 

 

I will let x be the number of CD's, and y be the number of DVD's.

 

The statement, "Sam has a total of 58 DVD's and CD's" can be written as the equation below.

x + y = 58 (Because the amount of CD's plus the amount of DVD's should add up to 58)

 

Also the statement, "If the number of CD's is two more than three times the number of DVD's" can be written as an equation.

x = 2 + 3y (Three times the number of DVD's is 3y, and two more means to add 2).

 

 

Now you have a system of two equations, with two variables that you can solve for.

 

x+y = 58

x = 2+ 3y

 

 

Using substitution method, you can get..

(2+ 3y) + y = 58

Now solve for y

2+ 4y = 58

4y=56

y= 14. 

So there are 14 DVD's

 

You can solve for the number of CD's by substituting y=14 into one of the equations.

 

x = 2 + 3y

x = 2 + 3(14)

x = 2 + 42

x= 44

 

So theres 44 CD's and 14 DVD's, which adds up to a total of 58 CD's and DVD's