This question is pertaining to College Algebra

Question

The sum of the squares of two positive consecutive odd integers is 202

Answer 1

I1 = x; I2 = x+2

(sum both integers)

x² + (x+2)² = 202

x² + x² + 4x + 4 = 202

(combine like terms)

2x² + 4x + 4 = 202

(set to =0)

2x² + 4x - 198 = 0

(divide by 2 (easier))

x² + 2x - 99 = 0

(factor)

(x + 11)(x - 9) = 0

x = -11; x = 9

(equation calls for positive integers only)

I1 = 9; I2 = 11

 

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