Algebra - Rectangle word problem

Question

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the? length, find the dimensions of the rectangle.

 

I was able to find the width through the equation:

x^2 + (2x+59)^2 = (2x+61)^2

with the width being equal to 20 inches, however I am struggling to find the length, and I want to be sure I am calculating it right.

 

Thank you in advance!

Answer 1

You got the hard part! 

 

2(20) + 59 = 40 + 59 = 99 inches.

 

I have a feeling you were overthinking!