7-i/9+i write in standard form a+bi

Question

 write in standard form. 7-i/9+i

Answer 1

Do you mean (7-i)/(9+i)?

 

If so, multiply the numerator and denominator by (9-i) to get:

 

[(7-i)(9-i)]/[(9+i)(9-i)] = (63 - 16i - 1)/82

 

                                  = (62 - 16i)/82

 

                                  = (31/41) - (8/41)i

Answer 2

7 - i/9 + i

7 + i - i/9

7 + 9i/9 - i/9

7 + 8i/9

or 

7 + (8/9)i