
Peter D. answered 09/04/16
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Physics PhD/Math BS + Programming:C/C++/Java + OS:Unix/Linux/Scripting
Let f(x)=xexp(x)
M(t) = ∫–∞∞ exp(tx)f(x)dx
= ∫ d[exp(x(t+1))/(t+1)]x (do integration by parts)
M(t) = (x/(t+1))(exp(x(t+1)) - ∫dx(exp(x(t+1))/(1+t) evaluated at x = -inf and +inf or
M(t) = (x/(t+1))(exp(x(t+1)) - exp(x(t+1))/(t+1)(t+1) evaluated at x = -inf and +inf.
M(t) = [(x/(t+1)) -1/(t+1)(t+1)]exp(x(t+1) evaluated at x = -inf and +inf.
This diverges.