Evan H. answered 08/24/16
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I assume by B' you mean the complement of B.
A U B' is the union of A and B', thus all members in A and all members in U-B (U-B = {w,1,2}) which is {w, y, 1, 2}
I assume n(P) = the cardinality(number of elements) of P. Then as (B-A) = {x,3} (All elements in B that aren't in A), the cardinality is 2.
AxB is the Cartesian product, which is {(a, b) | a in A and B in B} or {(2,x), (2, y), (2,3), (y, x), (y,y), (y,3)}
A U B' is the union of A and B', thus all members in A and all members in U-B (U-B = {w,1,2}) which is {w, y, 1, 2}
I assume n(P) = the cardinality(number of elements) of P. Then as (B-A) = {x,3} (All elements in B that aren't in A), the cardinality is 2.
AxB is the Cartesian product, which is {(a, b) | a in A and B in B} or {(2,x), (2, y), (2,3), (y, x), (y,y), (y,3)}
Aicha K.
08/24/16