
James B. answered 08/01/16
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Let A = # of type A vials
Let B = # of type B vials
38.85A + 30.34B = 1417.84 (Equation 1)
A + B = 40 (Equation 2) ..... total of 40 vials
Solving for A in equation 2 ...
A = 40 - B
Substituting "40 - B" for A in eqiation 1 ...
38.85A + 30.34B = 1417.84
38.85(40 - B) + 30.34B = 1417.84
1554 - 38.85B + 30.34B = 1417.84
1554 - 8.51B = 1417.84
1554 - 1417.84 = 8.51B
136.16 = 8.51B
136.16/8.51 = B
B = 16
Since A + B = 40
A + 16 = 40
A = 40 - 16
A = 24
There are 24 type A vials and 16 type B vials.