Let x = the time taken for both Henry and Felipe to prepare the trays.
Therefore, amount of work (unit rate) done per hour = 1/x
Assuming they work at a constant rate, then,
Work done by Henry in 1 hour + Work done by Felipe in 1 hour = Work done by both men in 1 hour
(1/10.1) + (1/12.1) = 1/x
LCD of all denominators = (10.1)(12.1)x = 122.21x
Multiply each side by 122.21x:
122.21x[(1/10.1) + (1/12.1)] = 122.21x(1/x)
12.1x + 10.1x = 122.21
22.2x = 122.21
x = 122.21/22.2
x = 5.5
Therefore, it will take them 5.5 hours to prepare the trays if they work together.