At 2063 feet how long would it take an object to free fall to the gound?

Question

Please respond with explaination of the problem.  How did you get this answer?  Thanks

Answer 1

A given height s has an equation of s = s₀ - v₀t - g/2 * t², where s₀ is the original height of the object, v₀ is how fast the object is falling at height s₀ and g = 32 ft/sec2 the acceleration of gravity,

 

When it is at a height of s₀ = 2063 ft and just dropped, v₀ = 0 ft/sec.

When it hits the ground, s = 0 ft

 

Putting these values into the equation results in 0 = s₀ - 0*t - g/2 * t²

                                                                  g/2 * t2 =s₀

                                                                  t = √(2s₀/g)

 

With s0 = 2063 ft, t = √(2063)/4 ≈ 11.355 sec