Norbert W. answered 07/29/16
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Consider a sphere and a Great Circle that create two hemispheres. Around this circle circle would be 360 dimples.
Suppose this is similar to the Earth and this is the equator. Do not count these points.
For each of these points on the equator, consider the great circle that goes from the equator through the poles, i.e. the North and South poles. The poles would be on all these circles. For each of these circles there are 178 dimples on the hemisphere from N to S. A hemisphere is considered because there would no duplicated dimples. Since there are 360 points on the equator, then each of these has 178 dimples, which would be 360*178 dimples. Add to this the two dimples for the poles. Then the total number of dimples would be 360*178 + 2 = 64082
Mark M.
Got to thinking about this. Would not the dimples get closer together as they proceed from the "equator" to either pole (are at a higher latitude) thus negating the condition that all dimples are one degree apart?
In other words, the dimples might be one degree apart at the "equator" yet would be closer together at 45° north latitude.
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07/29/16
Norbert W.
The question stated one dimple for every degree on any circumference, i.e. circle. It was with this in mind that I went about the solution. I know the earth really is not a perfect sphere, I just used this as a reference to describe a possible solution. The question never actually indicate how close the dimples are to each other, just that they occur at every degree on any circle. If some dimples overlap near the pole, I am not sure how to account for them.
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07/29/16
Rob J.
Norbert,
I like your answer b/c you honored my condition of 360 degrees for a circumference. the examples I used of golf
ball and Earth were meant to be opposites, as in, one huge and one tiny. The answer should be the same for
both. It's just that the distance between the points will vary. And this variance will change with every possible
volume of sphere, infinitely so. But the number of points in this scenario will be the same in every case. Don't fret
about some imaginary poles on Earth, b/c the Earth example is simply, in my mind, a large sphere for an example.
Again, thanks. I'm going with your answer, which I need for something I'm going to publish, as an example of some-thing.
I don't understand your answer, but you considered my guidelines. Is anybody else conflict this? Or is it true?
I guess I could build a model and count them, but I thought this piece of math trivia would be easily found and well
known.
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07/29/16
Mark M.
07/29/16