Rob J.

asked • 07/29/16

On any sphere. w/ 360 degrees per each circumference solve for x the total of one degree points, regardless of volume, on each and every sperical surface

 I take a golf ball.  I design it with exactly one dimple per degree of any proposed circumference.  Many of the
various circumferences intersect, which means subtracting 2 degrees from all but the first circumference.  With
my question I'm inserting a condition that every dimple is exactly one degree from every other dimple.  
 
I've searched this question online and am thwarted by not being able to pose it in a manner that a search
will solve it.
 
Any sphere, no matter whether the radius is one inch or one mile will have, as a math truth, exactly 360 degrees
on any circumference.  The distance between the points that represent the degrees points may be micro inches or
acres, but 360 is the max. 
 
Now this given, how many of these points, these acres for instance, are there on any and every sphere?
 
And why can't I find this one and only answer online.
I think it is 360 x 358 = 128,880

1 Expert Answer

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Norbert W. answered • 07/29/16

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Mark M.

Great demonstration of the force of mathematical reasoning!
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07/29/16

Mark M.

Got to thinking about this. Would not the dimples get closer together as they proceed from the "equator" to either pole (are at a higher latitude) thus negating the condition that all dimples are one degree apart?
In other words, the dimples might be one degree apart at the "equator" yet would be closer together at 45° north latitude.
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07/29/16

Norbert W.

The question stated one dimple for every degree on any circumference, i.e. circle.  It was with this in mind that I went about the solution.  I know the earth really is not a perfect sphere, I just used this as a reference to describe a possible solution.  The question never actually indicate how close the dimples are to each other, just that they occur at every degree on any circle.  If some dimples overlap near the pole, I am not sure how to account for them.
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07/29/16

Rob J.

Norbert,
I like your answer b/c you honored my condition of 360 degrees for a circumference.  the examples I used of golf
ball and Earth were meant to be opposites, as in, one huge and one tiny.  The answer should be the same for
both.  It's just that the distance between the points will vary.  And this variance will change with every possible
volume of sphere, infinitely so.  But the number of points in this scenario will be the same in every case.  Don't fret
about some imaginary poles on Earth, b/c the Earth example is simply, in my mind, a large sphere for an example.
Again, thanks.  I'm going with your answer, which I need for something I'm going to publish, as an example of some-thing.  
I don't understand your answer, but you considered my guidelines.  Is anybody else conflict this? Or is it true?
I guess I could build a model and count them, but I thought this piece of math trivia would be easily found and well
known.  
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07/29/16

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