
Arturo O. answered 06/07/16
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h = 7 cos (pi/3 * t)
h/7 = cos (pi/3 * t)
(pi/3 * t) = cos^-1(h/7)
t = (3/pi) * cos^-1(h/7)
Now keep in mind that the inverse cosine is multivalued, so there will be infinitely many t's coming out of this, because of the periodicity of the cosine.