Hannah M.
asked 05/30/16
Circle A and circle B intersect at points C and D. Each circle has radius 6 in. and AB = 8 in.
Carl M.
answered 05/30/16
Pre-Algebra, Algebra 1, Algebra 2 and Geometry Tutoring
Assuming that the value of AB = 8 in is the distance between the centers of each circle A and B, respectively.
- Set up a right triangle ACI where I is the intersection of the of CD and AB.
- AI is half of AB which is 1/2(8) = 4 in.
- AC is the radius of the circle r = 6 in.
- Use Pythagorean Theorem to find CI.
(AC)
2 = (CI)
2 + (AI)
2
- 62 = CI2 + 42
- 36 = CI2 + 16
- 36 - 16 = CI2
- 20 = CI2
- ±√20 = CI Use the positive value since distance cannot be negative.
- √20 = CI Double this value to find CD.
- CI = 2* √20 = 2√20 in = 4√5 in.
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Hannah M.
05/30/16