Larry C. answered 05/26/16
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Since each die has 6 sides, there are 6*6 or 36 possible combinations. Of those, each of them have a 5/6 chance of NOT showing a 5 or 25/36 total possibilities. Thus, there is a 11/36 chance that there is at least one 5, but we want exactly 1 showing. By eliminating the double-5 possibility, the total probability is 10/36 or 5/18 to show one and only one 5.