
David W. answered 05/18/16
Tutor
4.7
(90)
Experienced Prof
"what was the average speed in km/h of the team for this 2000 m event?"
2000 m / (5 min 20 sec)
2 km / (5 min 20 sec) (1000 m = 1 km)
2 km / (320 sec) (1 min = 60 sec)
2 km / (320/3600 hr) (1 hr = 3600 sec)
2 * (3600/320) km/hr (to divide by fraction, invert and multiply)
22.5 km/hr
"how many strokes did the team make to complete the race?"
(5 min 20 sec)*(36 strokes/min)
(320 sec)*(36/60 strokes/sec) [1 min = 60 sec]
(320)*(36/60) strokes [note: sec cancel out]
192 strokes [note: we could have multiplied (16/3 min)*36 strokes/min]
"how far did the team travel with each stroke?"
(total distance) / (number of strokes)
2000 m / 192 strokes
10.4 m/stroke [rounded]