Cameron's aquarium is 35 inches long, 20 inches wide, and 2 and 1/2 feet tall.

Question

Cameron's aquarium is 35 inches long, 20 inches wide, and 2 and 1/2 feet tall. How much water does he need if he wants to waterline to be 1 inch below the top? Express your answer two ways: in cubic inches and in cubic feet.

Answer 1

"aquarium is 35 inches long, 20 inches wide, and 2 and 1/2 feet tall"

"aquarium is 35 inches long, 20 inches wide, and 30 inches tall"        [1 foot = 12 inches]

 

Volume of aquarium= length * width * height

           V = 35 in * 20 in * 30 in

           V = 21000 in³

 

Now, you may convert 21000 in³ to 12.15 ft³ by dividing by (12*12*12)

  [the problem didn't ask for this].      [note: 1 ft³ = 12 in * 12 in * 12 in]

 

The water is 1 inch below the top.  That airspace is 35*20*1= 700 in³.

The water needed is 21000-700 = 20300 in³.    [note: this is also 35*20*29]

The water needed is 20300/(12*12*12) = 11.75 ft³.

Answer 2

We would just need to consider the height to be 1.5 instead of 2.5. Everything remains the same, where the volume of the aquarium is length X width X height.

 

Which is 35 X 20 18 = 12,600in cubed