how would you solve this: 4sin^2x=3? using interval [0,2pi]

Question

This is for my homework question

Answer 1

Your equation can be turned into (sin x)² = 3/4, so sin x = ±√(3) / 2.

 

You ought to recognize that x = 60^o springs to mind; other angles will be 120^o, 240^o and 300^o.

 

I'll leave it to to represent these four answers in radian measure.