William S. answered • 12/04/13

Tutor

4.4
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Experienced scientist, mathematician and instructor - William

Dear Erica,

In general

A = A

_{0}e-^{kt}where A is the amount remaining after t years, A

_{0}is the starting amount and k is the decay constant.Let us rewrite this as

A/A

_{0}= e^{-kt}= e^{-[(0.00012)*(4000)]}= e^{-0.48}= 0.62I think all we can say with certainty is that, during those 4000 years, the amount of C-14 decreased to 62% of its original value, or it lost 38% of its original value (A

_{0}).