Syed R. answered 04/24/16
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In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.
So plug in t=0 into your quadratic equation:
h(0) = -16.1(0^2) + 150
h(0) = 0 +150
h(0) = 150 ft is the height from where ball is dropped.
When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.
0 = -16.1t^2 + 150
16.1 t^2 = 150
t^2 = 150/16.1
t = sqrt(150/16.1)
t = ± 3.05
Since time cannot be negative, your answer is positive solution i.e. t = 3.05