Claire H.

asked • 04/23/16


show that ∫dx/(2+3sinx) [upper limit pi/2, lower limit 0] = ∫dt/((t+ 3/2)2 - (√5/2)2) [ upper limit 1, lower limit 0]
I know that sin(x) = 2t/(t2+1), where t = tan(x/2) but i cannot get the answer they are asking for in the question. Help would be appreciated.

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