
Kenneth S. answered 04/15/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
∫ (e2x+1)3 e2x dx is the problem.
Let u = (e2x+1);
then du = 2e2xdx or ½du = e2xdx, so you can write the desired integral as
½∫u3du and you can take it from here.
The trick, often useful, is to see that a substitution can be made making a substitution for a non-trivial expression, recognizing that another factor in an integrand will be essentially the inner (chain rule) derivative.

Kenneth S.
Use change-of-base formula; log z = (ln x)/ln 10. If z = e4x-3 then ln z = 4x-3. A vast simplification. You take it from here.
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04/15/16
Robert S.
04/15/16