3y + 7 3y + 7
-------- ÷ ---------
5y + 2 4 + 2
3y + 7 4 + 2
-------- * -------
5y + 2 3y + 7
-------- * -------
5y + 2 3y + 7
6
--------
5y + 2
Ralph L.
tutor
I can't find anything wrong with the answer.
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11/27/13
Jason S.
David, did you leave a y out of the denominator of the second fraction?
Was the problem (3y+7)/(5y+2) divided by (3y+7)/(4y+2)?
If so, the answer would have been:
4y+2
-------
5y+2
Just a guess because it didn't have a y in it.
I concur with Ralph's answer given the problem as it was submitted.
Just a guess because it didn't have a y in it.
I concur with Ralph's answer given the problem as it was submitted.
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11/28/13
David M.
11/27/13