Raymond B. answered 3d
Math, microeconomics or criminal justice
spotlight shines on a wall 12 meters away
man 4 meters from the wall walks towards the wall at a speed of 1.6 m/sec
man is 2 meters tall
how fast is his shadow on the wall decreasing??
construct 2 right triangles, one inside and congruent to the larger
for the larger
base = b = 12 m
b' = 1.6
length of man's shadow on the wall = a
light beam's length from man's head to the wall = h= 3sqr17
find a' = speed of shadow on wall
smaller has base=12-4=8 m
height=2 m
hypotenuse= sqr68=2sqr27
h'= about -1.6745 m/s
it's a related rates problem. plug in known values and solve for a'
a'=(hh'-bb')/a= h'sqr17- 6.4
in one second a goes from 3 to 2.5 m, a'= -1/2 m/sec