integral 3x^3/(7x^4+8)

Question

evaluate the following integrals

 

Answer 1

Let u=7x⁴ + 8

 

then du=7*4x³ or 28x³

 

 3x³/(7x⁴ + 8) becomes (3/28)*(1/u)*du

 

Integral of (3/28)*(1/u)*du is (3/28)*ln(u) + C

 

Final answer: (3/28)*ln(7x⁴ +8) + C