Jason S. answered 11/26/13
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Arthur D's answer is perfectly fine.
You can do it another way if you factor by grouping...
(7x^3+35x^2) + (7x + 35)
7x^2(x+5) + 7(x+5)
(7x^2 + 7)(x+5)
Factor out a 7 from the first one:
7(x^2 + 1)(x + 5), which, since multiplication is commutative, is equivalent to:
7(x + 5) ( x^2 + 1)