how much liters of each must be mixed to prepare the solution

Question

A labortory assistance wants to make 10 liters of 40% acid solution. If solutions of 50% and25% are available in the laboratory.How many liters of each must be mixed to prepare the solution

Answer 1

Stephany, we need to create a system of equations.

 

If x = the amount of 50% and y = the amount of 25%.

 

We are given that x + y = 10, because we need 10 liters of mixture.

 

.5x + .25y = .4(10)

.5x + .25y = 4

 

I bet you can solve it from here!