need help with me algebra 2

Question

Part 1: Find the slope of the line that passes through the points (-2, 1) and (0, 1).

Part 2: Write the point-slope form of the line that passes through the points (-2, 1) and (0, 1).

Part 3: Write the slope-intercept form of the line that passes through the points (-2, 1) and (0, 1).

Answer 1

Part 1)

The slope of a line is

 

m = (y₂ - y₁) / (x₂ - x₁)

 

where:

Point 1 = (-2, 1)

Point 2 = (0, 1)

 

m = (1 -1) / (0 - (-2))

m = 0

 

 

Part 2)

 

Point-slope form is       (y - y₁) = m(x - x₁)

 

where:

m = slope

(x₁ , y₁) is any of the points the line passes through.  Lets use (-2, 1).

 

y - 1 = 0(x - (-2))

 

y - 1 = 0(x + 2)

 

 

Part 3)

 

Solve for y from the previous answer.

 

y = 0(x + 2) + 1

 

y = 1

 

 

We have this equation because the y-coordinate for both points are the same.  The line is horizontal.

 

 

 

 

Answer 2

Hello Brian

 

1) Slope is the rise over the run

 

In terms or x and y it is (y₂-y₁)/(x₂-x₁)

m = (1-1)/(0-(-2)) = 0

 

2) the point slope form of the line utilizes the following equation format.

y-y₁ = m(x-x₁)

Using the 2nd point (you can actually use either one)

y-1 = 0(x-0)

y-1 = 0

 

3) for the slope intercept form, isolate the y variable

y-1 = 0

y = 1