the chalkboard in the algebra classroom covers 88 square feet of area. If the length is 5.5 times the height, what are the dimensions of the board?

Question

1. i need steps for it
2. i need exact solution

Answer 1

The area of a rectangular chalkboard is found

by multiplying length by width.  In this case

the height substitutes for the width since we

are merely looking at a rectangle standing on

one edge.

A = LW

 

We know the area is 88 ft² so

 

LW = 88

 

 

We also know the length is 5.5 times the width.. (height in this case)

L = 5.5W

 

Replace L with 5.5W in the equation LW = 88

 

5.5W(W) = 88

5.5W² = 88

divide both sides by 5.5

W² = 88/5.5

W² = 16

Take square root of both sides

W = √16

W = 4 ft

 

The height of the chalkboard is 4 ft

 

The length is 5.5W = 5.5(4) = 22 ft

 

The chalkboard is 22 ft long by 4 ft high