What is the length and width of a rectangle with a perimeter of 46 ft and a width that is 3 ft less than twice the length?

Question

What is the length and width of a rectangle with a perimeter of 46 ft and a width that is 3 ft less than twice the length?

Answer 1

Let l = the length  The width = L-3.  

If the perimeter is always 2 lengths and 2 widths

 

L+L  + (L-3) + (L-3)=46

 

Now clear the parentheses

 

L + L +L -3 +L -3=46

 

Collect your L's on one side, numbers on the other.  

4L = 46 +6 or 52 

 

The length is 13

The width is 10 (the length minus 3)

 

 

 

2