David M.
asked 11/15/13Select the answer that best completes the given statement
Because 2x^3-x+5 divided by x+1 equals 2x^2-2x+1 with a remainder 4, it follows 2x^3-x+5=
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2 Answers By Expert Tutors
Inactive Tutor answered 11/15/13
Tutor
New to Wyzant
(x+1) (2x2 - 2x + 1) + 4/(x+1)
Inactive Tutor
In fact,
2x^3-x+5 = [(x+1) (2x2 - 2x + 1)] + 4/(x+1)
2x^3-x+5 = [(x+1) (2x2 - 2x + 1)] + 4/(x+1)
Exactly.
Whoever marked this as not approved is incorrect.
Whoever marked this as not approved is incorrect.
Report
11/17/13
Inactive Tutor
Forgot to superscript the exponents.
2x3 - x + 5 = [(x + 1) (2x2 - 2x + 1)] + 4/(x + 1)
Exactly.
Whoever marked this as not approved is incorrect.
2x3 - x + 5 = [(x + 1) (2x2 - 2x + 1)] + 4/(x + 1)
Exactly.
Whoever marked this as not approved is incorrect.
Report
11/17/13
Inactive Tutor answered 11/16/13
Tutor
New to Wyzant
I agree with David's comment that you should post the entire question. Nonetheless, it seems pretty obvious that they are looking for you to make the connection that division problems with polynomials can be "put back together" just like problems without variables.
For example:
7/3 = 2 (mod 1)
which means
3*2+1 = 7
In your case:
(2x^3-x+5)/(x+1) = 2x^2-2x+1 (mod 4)
means
(x+1)*(2x^2-2x+1) + 4 = 2x^3-x+5
BTW, (mod x) is how remainders are written in formal math.
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Inactive Tutor
11/16/13