Jason S. answered 11/15/13
Tutor
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My goal is the success of my students. Knowledge-Patience-Honesty
Pascal's Triangle, find n = 3
(x+y)n
n = 0 1
n = 1 1 1
n = 2 1 2 1
n = 3 1 3 3 1
x = 3a
y = 5
n = 3
1(3a)3(5)0 + 3(3a)2(5)1 + 3(3a)1(5)2 + 1(3a)0(5)3
27a3 + 3(9a2)(5) + 9a(25) + 125
27a3 +135a2 + 225a + 125
Or brute force:
Or brute force:
(3a + 5)(3a + 5) (3a + 5)
First two using FOIL:
(9a2 + 30a + 25)(3a + 5)
Distribute:
(27a3 + 90a2 + 75a) + (45a2 + 150a + 125)
27a3 + 135a2 + 225a + 125