Nami G.
asked • 03/20/16Solve the system by elimination. First clear the denominator...
5x-1 / 3 + y+7 / 4 = 11
x+1/2 - x-y/3=3
Find the solution set
The 5x-1 is over 3, the y+7 is over 4
Find the solution set
The 5x-1 is over 3, the y+7 is over 4
x+1 is over 2, x-y is over 3
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1 Expert Answer
Alan G. answered • 03/20/16
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The LCD is 12. Multiply both sides by 12 to clear the fractions:
12(5x - 1)/3 + 12(y + 7)/4 = 12(11)
4(5x - 1) + 3(y + 7) = 132
20x - 4 + 3y + 21 = 132
20x + 3y + 17 = 132
20x + 3y = 115.
There is no solution in numbers until a second equation is provided.
Nami G.
I have edited the question, forgot the second equation.
Report
03/20/16
Alan G.
Okay. Multply the second equation by its LCD, which is 6:
6(x+1)/2 - 6(x-y)/3 = 6(3)
3(x+1) - 2(x-y) = 18
3x + 3 - 2x + 2y = 18
x +2y = 15.
Now you have the system of equations,
20x + 3y = 115
x+ 2y = 15.
Label the first of these [1], the second [2].
2[1] -> 40x + 6y = 230
-3[2] -> -3x - 6y = -45
Add these together:
37x = 185
x= 5.
Get y by plugging in x = 5 into [2] and solving for y:
5 + 2y = 15
2y = 10
y = 5.
The solution is (5,5).
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03/20/16
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03/20/16