The principal fourth root of (x^8)(y^12) is:

Question

(x^4)(y^6)/2

(x^2)(y^3)

(x^4)(y^8)

(x^4)(y^6)

Possibly not a real number, depending on the value of x and y

Answer 1

x^8=(x^2)(x^2)(x^2)(x^2)

y^12=(y^3)(y^3)(y^3)(y^3)

(x^2)(y^3) answer