
Candace S. answered 03/13/16
Tutor
4.9
(28)
A day without Math is like a day without sunshine!
Hi Seth,
Could someone help with this equation?
Multiply or divide as indicated. Be sure to reduce all answers to lowest terms.
(a2+5a)/(3a) • (4a2)/(a2-4a)
Multiply or divide as indicated. Be sure to reduce all answers to lowest terms.
(a2+5a)/(3a) • (4a2)/(a2-4a)
Factor
a(a+5) 4a2
------- • --------
3a a(a-4)
In the 1st term the a's can be cancelled
(a+5) 4a2
------- • --------
3 a(a-4)
------- • --------
3 a(a-4)
In the 2nd term an a can be cancelled
(a+5) 4a2
------- • --------
3 (a-4)
------- • --------
3 (a-4)
That's as far as the terms can be reduced
4a(a+5) 4a2+20a
--------- = ------------
3(a-4) 3a-12