
Dante H. answered 03/13/16
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(2y+4)/(5y-5) ÷ (5y+10)/(4-4y)
= (2y+4)/(5y-5) x (4-4y)/(5y+10) [NOTE WE FLIPPED NUM AND DEM ON SECOND TERM]
= ((4-4y)(2y+4)) / ((5y-5)(5y+10))
= ((4-4y)2(y+2)) / ((5y-5)5(y+2))
= ((4-4y)2) / ((5y-5)5) [NOTE WE CANCELED THE (Y+2)]
= ((4-4y)2) / ((5y-5)5) [NOTE WE CANCELED THE (Y+2)]
= ((4-4y)2) / ((5y-5)5)
= (-4(-1+y)2) / (5(y-1)5)
= (-4(y-1)2) / (5(y-1)5)
= ((-4)(2))/((5)(5))
= -8/25