Hi Jared,
Let's factor both expressions first.
r2-5r = r(r-5)
r3-3r2-10r = r(r2-3r-10) = r(r-5)(r+2)
And now let's substitute these factors into the original expression.
r(r-5)
-------------
r(r-5)(r+2)
In this form, we can see that there is both an r and an r-5 term in both the numerator and denominator
So the expression reduces to
1
-------
(r+2)