Youngkwon C. answered 03/11/16
Tutor
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Knowledgeable and patient tutor with a Ph.D. in Electrical Eng.
Hi Malachi,
One of the references
from which we can get a concise summary of the theorem is
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/thevenin.html.
Looking at the very top of the website above, and
let R1 = 3kΩ, R2 = 10kΩ, R3 = 6kΩ, and V1 = 10V,
the Thevenin voltage, e, can be calculated as
e = V1R3/(R1 + R3)
= 10·6/(3 + 6)
= 10·6/9
= 6.67V
The Thevenin resistance, r, is
r = (1/R1 + 1/R3)-1 + R2
= (1/3 + 1/6)-1 + 10
= 2 + 10
= 12kΩ
So, the equivalent circuit seen through two terminals
will look like a serial connection of
the Thevenin voltage, 6.67V, and
the Thevenin resistance, 12kΩ.
Hope this helps.