
Andrew M. answered 03/11/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
(8r2+26rs+15s2)/(25s2-4r2)
NUMERATOR:
8r2 + 26rs + 15s2
Let's try to factor by grouping.
Multiply the coefficient of the r2 term
by the coefficient of the s2 term:
8(15) = 120
We need to find factors of 120 that add
to the coefficient, 26, of the rs term.
6(20) = 120, 6+20 = 26
Separate 26rs out to 6rs + 20rs
8r2 + 26rs +15s2
= 8r2+6rs+20rs+15s2
Grouping this for factoring
(8r2+6rs) + (20rs + 15s2)
= 2r(4r+3s) + 5s(4r+3s)
= (2r+5s)(4r+3s)
DENOMINATOR:
25s2-4r2
This looks like the difference of two squares.
25s2 = (5s)2 and 4r2 = (2r)2 so
25s2-4r2= (5s)2-(2r)2 = (5s-2r)(5s+2r)
Putting back together:
(8r2+26rs+15s2)/(25s2-4r2)
= (2r+5s)(4r+3s)/(5s-2r)(5s+2r)
Cancelling out the common factor of 5s+2r we have
(4r+3s)/(5s-2r)