
Andrew M. answered 03/11/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
(x3-1)/(x2-2x+1)
First look at the numerator (x3-1)
This is the difference of two cubes.
(1)3 = 1
The formula for the difference of two cubes is
a3-b3 = (a-b)(a2 + ab + b2)
For this polynomial a=x, b=1
x3-1 = (x-1)(x2 + x + 1)
Now look at the denominator x2-2x+1
x2-2x+1 = (x-1)2 = (x-1)(x-1)
Putting the rational expression back together
[(x-1)(x2 + x + 1)]/[(x-1)(x-1)]
Cancel the common factor (x-1)
(x2+x+1)/(x-1)