Jay, I hope you've incorrectly typed your work so far.
We can factor 3a out of the numerator...
3a(2a2 - 9a - 5)
We can further factor 2a2 - 9a - 5 into (2a + 1)(a - 5)
We can factor a out of the denominator...
a(2a2 + 11a + 5) = a(2a + 1)(a + 5)
3a(2a + 1)(a - 5)/a(2a + 1)(a + 5) = 3(a - 5)/(a + 5)
Hope this helps!