Hi Terry.
Let's factor each of the polynomials listed. Then set the factors equal to zero and solve for x
I
x2+x-6
(x+3)(x-2) = 0
x+3 = 0 x-2=0
x = -3, 2
So I has the right zeros
II x2-x-6
(x-3)(x+2) = 0
x-3 = 0 x+2=0
x = 3, -2
So II does not have the right zeros
(x-3)(x+2) = 0
x-3 = 0 x+2=0
x = 3, -2
So II does not have the right zeros
III 2x² + 2x - 12
2(x² + x - 6) = 0
2(x+3)(x-2) = 0
x+3 = 0 x-2 = 0
x = -3, 2
III does have the right zeros
I and III; the correct answer is 3)
Terry B.
03/10/16