PPerimeter of rectangle 500 yards length 90 what;s the width

Question

The perimeter is 500 yards.  What are the dimensions of the rectangle if the length is 90 yards more than the width?

Answer 1

The perimeter is found using the formula

 

P = 2L + 2W, where L is the length and W is the width.

 

Given that P = 500 yd and L = W + 90 (read the second sentence), you can substitute (plug in) W + 90 for L into the formula, then solve for L:

 

500 = 2(W + 90) + 2W

 

500 = 2W + 180 + 2W

 

500 = 4W + 180

 

4W = 500 - 180 = 320

 

W = 320/4 = 80

 

Then L = W + 90 = 80 + 90 = 170.

 

Thus, the dimensions of the rectangle are 80 yd and 170 yd. This can be checked by finding the perimeter from these dimensions.