Algebra II 7.

Question

Determine the maximum possible number of turning points for the graph of the function
f(x) = x5 (x5 + 6)(2x – 7).
Question 7 options:

1) 11

2) 20

3) 5

4) 10

Answer 1

Hi Carrie,

 

 

Algebra II

7.  Determine the maximum possible number of turning points for the graph of the function
f(x) = x⁵ (x⁵ + 6)(2x – 7).
Question 7 options:

1) 11

2) 20

3) 5

4) 10

 

 

f(x) = x⁵ (x⁵ + 6)(2x – 7).

 

in general to find the maximum number of turning points for a polynomial function, add up the value of the exponents and then subtract one  (because the factors are being multiplied)

 

x⁵(x⁵)(2x¹)

 

Even though you cannot see it, there is an exponent of 1 in the 2x term.

 

Adding the exponents,  5+5+1=11

Now subtract 1:  11-1=10

 

ANSWER:  The maximum number of turning points is 10 (option #4)